(Business Mathematics &Statistics)
2007-01-25 02:36:48 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The probability P of getting 7 throwing 2 dices is as follow:
There are a total of 36 possible combinations
the combinations totalling 7 are:
1,6
2,5
3,4
4,3
5,2
6,1
So a total of 6 combinations. So P = 6/36 = 1/6
The probability Q to get 7 twice in a row is
Q= P * P = 1/6 * 1/6 = 1/36
2007-01-25 02:55:57 · answer #1 · answered by catarthur 6 · 0⤊ 0⤋
Not sure entirely if you are asking:
1) What is the probability that he will throw a 7 on the first roll and then throw another 7 on the second roll.
Answer: 6/36 * 6/36 = 1/36
2) or What is the probability he will throw a 7 on the second roll irrespective of what the first roll was.
Answer = 6/36 = 1/6
2007-01-25 02:41:32 · answer #2 · answered by Will 4 · 3⤊ 0⤋
The chance on any one roll would be one in six (5 to 1).
To roll 7 on two consecutive rolls would be one in 36 (35 to 1)
7 is the most common number rolled on a pair of dice.
2 and 12 are the least common (35 to 1)
2007-01-25 02:49:02 · answer #3 · answered by pater47 5 · 0⤊ 0⤋
in case you throw the comparable die 7 situations, the possibility of having a 6 all 7 situations is (a million/6)^7 = 0.00000357 i don't comprehend what you mean by way of the 2nd area. Are you throwing 2 cube purely as quickly as, or throwing 2 cube 7 situations?
2016-12-12 19:57:13 · answer #4 · answered by degennaro 4 · 0⤊ 0⤋
it's the same probability of rolling 7 the first time. each roll is independent of the other.
2007-01-25 02:41:47 · answer #5 · answered by eriq p 4 · 0⤊ 0⤋