Chemistry question!?

Question

given a 1M solution of HAc, and that [H_3_0+] =.001 M, how would you calculate [Ac-] and [HAc] at equalibrium?

Answer 1

One piece of information you are missing, is the pKa of the acid. Obtain the pKa (or the Ka) of the acid, and solve it using the method outlined below for the concentration of Ac and HAc. (I assume that HAc is Acetic Acid.)

[H+][Ac-]/[HA]=Ka

[H+] = 0.001,
[HA] = F(Formal Concentration) - x = 1 - x;

Please let us know what you get.