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2007-01-25 02:14:16 · 7 answers · asked by Anonymous in Education & Reference Homework Help

When I'm doing questions like these I am looking for x right?

2007-01-25 02:15:31 · update #1

7 answers

Yes, you are solving for x. In this case x=-1 or 13.

2007-01-25 02:19:28 · answer #1 · answered by tarl_cabot_2k 2 · 0 0

solution:
For an equation involving absolute value expression, as long as the number equals to the term w/ absolute value expression(in this case it's I6-xI) is positive (in this case, it's 7), there's always a possible solution. The value of the number inside the absolute value symbol is either positive or negative, hence we have:

6 - x = 7
-x = 7-6
( -x = 1)(-1)
x = -1

or

6 -x = -7
-x = -7 -6
( -x = -13)(-1)
x = 13

so the solution set is {-1, 13}

2007-01-25 10:37:43 · answer #2 · answered by baeyongmok 2 · 0 0

To solve l6-xl=7, set 6-x equal to 7 and -7 and solve from there. There will be 2 answers.

6-x=7
x=-1

6-x=-7
x=13

2007-01-25 10:18:14 · answer #3 · answered by Ben B 4 · 2 1

"What would make a problem no solution? "

An equation is solvable as long as you have the same number of variables as independent equations. This is the simplest case one variable one equation.

2007-01-25 10:23:59 · answer #4 · answered by G's Random Thoughts 5 · 0 0

yes you are looking for x

6-x=7 or 6-x=-7
x=-1 or x=13

it is solvable

2007-01-25 10:35:28 · answer #5 · answered by edwarjd 3 · 0 0

when u have the bars around the problem though, I think that the answer will only be the positive number.

2007-01-25 10:23:05 · answer #6 · answered by mrs. greatness 2 · 1 0

1=x dude what grade r u in not 2 be condescending but im 13 and in Pre Algebra hope i helped

2007-01-25 10:22:57 · answer #7 · answered by breezybeautiful 2 · 0 2

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