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Chmistry question?

given a 1M solution of HAc, and that [H_3_0+] =.001 M, how would you calculate [Ac-] and [HAc] at equalibrium?

2007-01-25 01:58:45 · 1 answers · asked by BMac 3 in Science & Mathematics ➔ Chemistry

1 answers

Consider HAc <-----> H+ + Ac-.

It is immediately obvious that [H+] = [Ac-] = 0.001M.

Every mole of H+ (or Ac-) that is produced is lost by HAc, so its concentration is 0.999M.

2007-01-27 08:59:48 · answer #1 · answered by Gervald F 7 · 0⤊ 0⤋

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