I would appreciate working and explanations :)
q: what would the common denominator to mulity each part be? 2x?
2007-01-24 20:39:36 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
yep, 2x.
2/x * 2x - 3/2x * 2x = 4 * 2x
4 - 3 = 8x
1 = 8x
x = 1/8
2007-01-24 20:45:27 · answer #1 · answered by asphyxia 3 · 0⤊ 0⤋
you multiply the right and left side by 2x
you obtain 4-3 = 8x
1=8x
x =1/8
verify you obtain 16-12 =4
2007-01-25 04:51:11 · answer #2 · answered by maussy 7 · 0⤊ 0⤋
2/x-3/2X=4
multiply both sides by 2X
2X divided by x equals 2 multiply by 2 = 4
2X divided by 2X equals 1 multiply by 3= 3
2X multiply by 4 = 8x
4-3=8x
1=8x
-------
8
X=1/8
2007-01-25 05:36:57 · answer #3 · answered by Princess Shai 3 · 0⤊ 0⤋
Step1: Get the LCD of both terms on the left side of the equation. (I assume you already know how to do this so let's get to Step2)
Step2: Merge both terms.
4 - 3 / 2x = 4. (Read as four minus three all over two x equals four)
Step3: Subtract.
1 / 2x = 4 (Read as one over two x equals four.)
Step4: Cross Multiply
*Assume that four has a denominator of one.
8x = 1 (Eight x equals one)
Step5: Divide both sides by eight to let 'x' remain by itself.
x = 1 / 8 (x equals one over eight)
2007-01-25 05:11:36 · answer #4 · answered by banana_otaku 2 · 0⤊ 0⤋
2/x - 3/2x = 4
(2/x x 2x) - (3/2x x 2x) = (4 x 2x)
4x/x - 6x/2x = 8x
4 - 3 = 8x
1 = 8x
1/8 = x
2007-01-25 04:54:09 · answer #5 · answered by J L 2 · 0⤊ 0⤋
(2x*2-3x)/2x^2 = 4
4x-3x=8x^2
x=8x^2
1=8x
x=1/8
2007-01-25 04:44:51 · answer #6 · answered by blitzkrieg_hatf6 2 · 0⤊ 0⤋
I AM AN ART MAJOR!
2007-01-25 04:42:17 · answer #7 · answered by Jzambales 1 · 0⤊ 1⤋