so how would i find the center and radius of a circle using:?

Question

these equations?

(x + 5)² + (y - 11)² = 49

x² + 12x + y² - 16y -44 = 0

Answer 1

what am i supposed to look for here?

Answer 2

(x-a)^2 + (y-b)^2 = r^2

with (a, b) as the center and r = radius

So, #1 is (-5, 11), r=7
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#2 you need to put in standard form:

x^2 + 12x + y^2 -16y - 44 = 0
x^2 + 12x + y^2 -16y = 44
(x^2 + 12x + 36) + (y^2 - 16y + 64) = 44 + 64 + 36
(x + 6)^2 + (y - 8)^2 = 144 = 12^2

So, the center is (-6, 8) and r = 12

Answer 3

The top equation is easy, the center of the circle is (-5,11) and the radius seven. The top equation is in the standard form;

(x - h)²+ (y - k)² = r²

this makes it easy to find the center, to find the x and y coordinates you equal (x - h) and (y - k) to zero so you get x = h and y = k. To find the radus its just the square root of r or in your case 49. You can use this on the second equation if you can put it into the standard form.

Answer 4

what is x and y ?

what's their relation with center and radius of a circle ?

Answer 5

Graphing...