need help...
f=15m/a (f equals 15 times m divided by a)
have to solve for m
2007-01-24 20:02:20 · 4 answers · asked by Miranda 2 in Science & Mathematics ➔ Mathematics
to THE LORD:
but if you multiply by a you have to do to both sides rite? so why is f/15? wouldnt it be f x a or something?
2007-01-24 20:11:16 · update #1
oh...i get it now. thx!
2007-01-24 20:12:03 · update #2
Both solutions are fine. It's just whether you show each baby step.
This is how I'd look at it. You want to isolate m. m is multiplied by 15 and divided by a. You have to undo those operations.
So.
f=15m/a, multiply both sides by a
fa = 15m
now divide both sides by 15
fa/15 = m you're done.
To solve for a variable that is all wound up with other variables and constants, you do operations that unwind the equation in order to isolate the variable of interest.
2007-01-24 20:17:20 · answer #1 · answered by modulo_function 7 · 0⤊ 0⤋
first multiply both sides by a/15 so that m will be left on the right side. the new formula is af/15=m (m equals a times f divides by 15)
2007-01-25 04:09:31 · answer #2 · answered by asphyxia 3 · 0⤊ 0⤋
f=15m/a
> m/a = f/15 ( multiply by a )
> m = fxa/15 or m = f * a / 15
2007-01-25 04:08:19 · answer #3 · answered by Anonymous · 0⤊ 0⤋
f=15m/a
cross multiply
af=15m
divide both side by 15 to cancel 15.
af/15=m
symmetric
m=af/15
2007-01-25 04:15:57 · answer #4 · answered by XFNET 2 · 0⤊ 0⤋