2007-01-24 17:04:37 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x*y=48
x+y=-26
solve the bottom for x: x=-26-y and substitute this into the first equation:-(26+y)*y=48
26y+y^2=-48
y^2+26y+48=0
(y+24)*(y+2)=0
y=-24 or y=-2
therefore, x=-2, y=-24 or x=-24, y=-2
2007-01-24 17:11:15 · answer #1 · answered by bruinfan 7 · 0⤊ 0⤋
a+b = -26 ,,, a b=48
b=-26-a ,,, a (-26 -a)=48
,,, -26 a -a^2 =48
a^2 +26 a +48 = 0
a^2 -(-24-2)+ [(-24)(-2)] =0
a1=-24 a2 = -2
b1=-26-(-2) =-26+2=-24
b2= -26 -(-24)=-26+24=-2
2007-01-24 17:23:09 · answer #2 · answered by Tuncay U 6 · 0⤊ 0⤋
2 and 24
2007-01-24 17:09:10 · answer #3 · answered by eastdurhamcop 1 · 0⤊ 3⤋
-24 and -2
2007-01-24 17:36:09 · answer #4 · answered by mediax12 1 · 0⤊ 0⤋
Hello,
24 x 2 = 48
24 + 2 = 26
2007-01-24 17:10:09 · answer #5 · answered by Anonymous · 0⤊ 2⤋
-2 and -24
2007-01-24 17:09:17 · answer #6 · answered by mattic 2 · 0⤊ 0⤋
-24 and -2
2007-01-24 17:08:44 · answer #7 · answered by Anonymous · 0⤊ 0⤋
xy=48
x+y=-26
x= -26-y
(-26-y)(y)=48
-26y-y²=48
y²+26y+48=0
(y+2)(y+24)=0
y= -2 or y= -24
Substiute -24 into x= -26-y
x= -2
Hence the 2 numbers are -2 and -24.
2007-01-24 17:09:52 · answer #8 · answered by A 150 Days Of Flood 4 · 1⤊ 0⤋
-24
-2
2007-01-24 17:13:14 · answer #9 · answered by Anonymous · 0⤊ 0⤋
xy = 48
x + y = -26
x + y = -26
y = -x - 26
x(-x - 26) = 48
-x^2 - 26x = 48
x^2 + 26x + 48 = 0
x = (-b ± sqrt(b^2 - 4ac))/(2a)
x = (-26 ± sqrt(26^2 - 4(1)(48)))/(2(1))
x = (-26 ± sqrt(676 - 192))/2
x = (-26 ± sqrt(484))/2
x = (-26 ± 22)/2
x = (-4/2) or (-48/2)
x = -2 or -24
ANS : -2 and -24
2007-01-24 18:24:05 · answer #10 · answered by Sherman81 6 · 0⤊ 0⤋