Find the possible dimensions(lenghts and widths) of rectangles with the given area. Then find the perimeters of these rectangles.
Area: 18 square units. Please help.
2007-01-24 16:26:40 · 3 answers · asked by pentium4 1 in Science & Mathematics ➔ Mathematics
Since length • width = area,
1 • 18 = 18 ...........p = 38
2 • 9 = 18 .............p = 22
3 • 6 = 18 .............p = 18
4 • 4.5 = 18 ..........p = 17
5 • 3.6 = 18 ..........p = 17.2
And that's just the 1st 5 integer values for length. As you can see, perimeter is minimum when length and width are equal.
2007-01-24 16:37:37 · answer #1 · answered by Philo 7 · 0⤊ 0⤋
um 2 x 9 p = 22
1x 18 p = 38
3 x 6 p = 36
2007-01-25 00:31:03 · answer #2 · answered by Mike jones 1 · 0⤊ 0⤋
1/18, 2/9, 3/6
2007-01-25 00:30:31 · answer #3 · answered by spartan_1117 3 · 0⤊ 0⤋