y = x - 1
to find the y intercept set x = 0, so in this case
y = 0 - 1
solve for y
y = -1
so your y intercept is y = -1, that is (0, -1)
to find the x intercept set y = 0 so in this case
0 = x - 1
solve for x, to do this add 1 to both sides
1 = x
so your x intercept is x = 1, that is (1, 0)
FOR THE SECOND ONE
2x-1=y
to find the y intercept set x = 0, so in this case
y = 2(0) - 1
solve for y
y = 0 -1
y = -1
so your y intercept is y = -1, that is (0, -1)
to find the x intercept set y = 0 so in this case
2x-1=0
solve for x, to do this add 1 to both sides
1 = 2x
divide both sides by 2
x = 1/2
so your x intercept is x = 1/2, that is (1/2, 0)
IF you need further explanation IM Me or Emal Me
EDIT: For your first one the line crosses the y-axis at -1 and the x-axis at 1.
For the 2nd one the line crosses the y-axis at -1 and the x-axis at 1/2.
2007-01-24 16:23:55
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answer #1
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answered by Anonymous
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Ok you will find this easy. Basically if you look at these they say y=x-1, and y=2x-1, they are basically the same when y is alone and by itself. Whatever happens though, y has to all ways be on one side by itself and not with any other variable or number otherwise you have work to do. In this case 1 is the y-intercept and x is the slope. use rise/run to plot equations on graphs. The base equation is "y=mx+b" but in your case m is (1 over 1 "1/1") since 1x is the same thing as x, and b is the y-intercept. So if you were to plot that on a graph for y=x-1 you would start at 1 (the y-intercept) and the from there go up 1, over 1 (hence rise/run). And for y=2x=1 (2x-1=y) you would go up 1 since the y-intercept is 1 and then from there you do rise/run so from up 1 (on the vertical grid going up and down, you would go up 2 over 1, and since 2 is by itself next to x you would but 2 over a 1 since that's what the slope is. The you connect the dot you made with the y-intercept (1) and another dot from up 2 over to the left 1 and it would be a sideways line. And note since it is -1 you would go down one on the vertical baseline instead of up and then go up from there unless the slope (m) was negative. Hope that helped! Please email by clicking on the picture and emailing me if you need a visual explanation or something. Good luck!
2007-01-24 16:29:05
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answer #2
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answered by Brandon 3
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The y intercept is quite simple. It is the number on its own (including the sign in front of it). For example, in y = x - 1, the y-intercept is -1. For y = 2x - 1, the y-intercept is also -1. If the equation were y = 5x + 3, the y-intercept would be positive 3.
X-intercepts are a little less obvious. To find the x-intercept, you make y equal to zero, then solve the equation to find what x is.
For example, in the equation y = x - 1, you rewrite that as 0 = x - 1. Then add one to both sides, and you end up with x = 1, which means that the x-intercept is 1.
In, say, y = 2x - 1, same idea. You would rewrite it as 0 = 2x - 1, which can be rearranged (by adding 1 to both sides) to make it 1 = 2x. Then divide both sides by two (to get x by itself), which makes x = ½. So the x-intercept is ½.
2007-01-24 16:25:01
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answer #3
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answered by Ben C 2
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Ok all that you have to do is plug in zero where the x is to get the y intercept and then do the same with the y to find the x intercept. so ....
x-1=y
(0)-1=y
-1=y this is the y intercept
x-1=y
x-1=(0)
x =1 this is the x-intercept
2007-01-24 16:23:46
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answer #4
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answered by blni0602 1
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to find an intercept, just replace the variable you ARENT trying to find the intercept of with zero.
so y intercept of y=x-1 :
y = 0-1
y intercept is 1 or (0,1) since you use (x,y) format
x intercept of y=2x-1 :
0 = 2x - 1
1 = 2x
1/2 = x
so x int is 1/2 or (1/2,0)
now in some cases like y = x^2 + 2x - 6 (parabolic) you will have more than one x intercept. in cases like x^2 + y^2 = 9 (circles) you will have 2 of each.
2007-01-24 16:19:42
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answer #5
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answered by Dashes 6
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those are slopes. so, for the first one, x-1=y, that equals y=1x-1.
you will use the formula y = mx +b (i think thats right, its been a while since ive taken math).
so you will look at your graph. anything that is multiplies by x (1) you will put on the x intercept. anything after that, (-1) will go on the y intercept. so you should have a dot on the 1 on the x line, and a dot on the -1 on the y line. you will then grab a ruler and draw a line through them.
now for question 2. y=2x-1
same way. you will mark 2 on the x intercept, and -1 on the y intercept. draw you a line through it, and your done.
2007-01-24 16:21:24
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answer #6
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answered by Josh 2
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Well go ahead and graph the whole equation(s) then just find the point where both lines cross, or Intersect, thats all you've gotta do, state at which point x and y cross(intercept).
2007-01-24 16:22:02
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answer #7
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answered by Unique Guy 2
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the ques u have asked is of linear equations.it can be solved as-
x-1=y and 2x-1=y
x-y=1 and 2x-y=1(by sending y and 1 here and there).now,
solve by subtracting these 2 equations.
2x-y-(x-y)=1-1
x=0 and y=-1
2007-01-24 16:35:16
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answer #8
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answered by suman 1
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lol, just use a graphing calculator
< calculus student also
2007-01-24 16:36:05
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answer #9
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answered by flaminyon123 2
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