3 log24 24^2/3?

Question

I know how to do problems like "log7 28" which are more simple but I dont know what to do with the other numbers.. can someone explain please?

Answer 1

3log(24)(24^(2/3))
log(24)((24^(2/3))^3)
log(24)(24^((2/3) * 3))
log(24)(24^(6/3))
log(24)(24^2)

ANS : 2

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log(7)28 =
log(7)(7 * 4)
log(7)7 + log(7)4

1 + log(7)(2^2)

or

log(7)(28) = (log(28))/(log(7)) = 1.7124

ANS : 1 + log(7)4 or 1 + 2log(7)2 or 1.7124

Answer 2

The log is the exponent: if a^b = c, then log (base a) of c = b.

I assume what you wrote means 3 • log (base 24) of 24^(2/3), so you get
3 • 2/3 = 2.