Anyone good at math, help please?

Question

i completed the problem but i dont know if its right, help would be appreciated

find the difference quotient of the function f(x)=x^3-5x

thanks

Answer 1

f(x)=x^3-5x
f(x+h) = x^3 +3x^2h +3xh^2 +h^3 -5x - 5h
The difference quotient is [f(x+h)-f(x)]/h
= [3x^2h +3xh^2+ h^3 -5h]/h
=3x^2 +3xh +h^2 -5

Answer 2

ax^b = a(b)x^(b-1)
ax^1 = a(1)x^1-1 , where; X^0= 1
so,
ans... 3x^2 - 5 ..........