Al+S8 yields Al2S3
Al(OH)3+HBr yields AlBr3+H2O
CH3CH2CH2CH3+O2 yields CO2+H2O
C2H6+O2 yields CO2+H2O
Al(OH)3+H2SO4 yields Al(SO4)3+H2O
H3PO4+Ca(OH)2 yields Ca(PO4)2+H2O
2007-01-24 14:14:44 · 3 answers · asked by †ღChristian♥Girlღ† 2 in Science & Mathematics ➔ Chemistry
http://www.nanday.com/balance/balance.php
Is a website that does it all for you if thats what you want if not I have some good notes i could give you... im learning it to
2007-01-24 14:24:48 · answer #1 · answered by Anonymous · 0⤊ 0⤋
First one only, then you do it! 1 Al +8 S on left ---2 Al /3S on right, LCM of Sulfur since it is more awkward (Aluminum is 1:2, easy)
is 24 because 3 and 8 both go into 24: so for every 3 Sulfurs you need 2 Al so you need 8 *2 or 16 Al. Final eqn: 16 Al + 24 S ---> 8Al2S3 (Read em and weep!)
Pay attention to your charges!
2007-01-24 14:42:56 · answer #2 · answered by lynn y 3 · 0⤊ 0⤋
do your own homework
seriously you already posted a ton of these
and just learn how to do them
you just count the number on one side and match with the other....
2007-01-24 14:23:11 · answer #3 · answered by BryanL 2 · 0⤊ 1⤋