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2007-01-24 14:04:34 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

y not (1,2] ?

2007-01-24 14:17:34 · update #1

3 answers

The range of this function (f(x) = 1+1/x^2) is (1,infinity). Since f(x) is not defined at the point 0, it never attains 1.

2007-01-24 14:10:23 · answer #1 · answered by goldenflaws 2 · 0 0

As x --> 0, 1/x^2 --> infinity
As x --> infinity 1/x^2 --> 0
So the range of y is [1, infinity]

2007-01-24 22:11:49 · answer #2 · answered by ironduke8159 7 · 0 0

(1,infinity), small values of x will give big values for y.

2007-01-24 22:11:05 · answer #3 · answered by Theta40 7 · 0 0

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