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okay so we have two equations x+y=1 and 2x-2y=6

how would you solve that then graph

directions read Solve by graphing then check algebraically

we have to give a point like ( 0, 0 ) then graph them


EXAMPLE:

x+y=4
2x-y=5

and the answer is 3,1

how would i graph each problems answer

2007-01-24 14:02:56 · 4 answers · asked by Nate K 2 in Science & Mathematics Mathematics

4 answers

Elimination
2(x+y=1)
2x-2y=6

2x + 2y =2
2x - 2y =6
_________
4x = 8
x = 2, x + y = 1, so y = -1

2007-01-24 14:09:32 · answer #1 · answered by leo 6 · 0 0

You must have a graph paper. Then start with equation 1 which is x + y =1
Now make a table write down values for x from negative numbers to positive nos.
For example you can give values of -4, -2, 0, +2, +6. Now put in the equation and find Y. For example when you put x = -2 in the equation you get:
-2+y =1. Therefore y=3. Therefore (-1,3) is a point on this equation. Now substitute all values of X given above in the same equation and find y for each value. Then put all these points on the graph paper and connect them. You get the line x + y =1
Do the same for the other line.
Wherever the 2 lines intersect read that value of x and y. That is your solution.

2007-01-24 22:16:53 · answer #2 · answered by Sam P 2 · 0 0

look both the equation is for one curve....
so u'l have to make a table and every time take different values of x and so u'l get a different value of y (like if x=0 in x+y=4,then y=4).then put the dots in the graph paper and join them all.

2007-01-24 22:09:09 · answer #3 · answered by tonima 4 · 0 0

first get it in y=mx+b form. insertthen plot the y-intercepts(b) then use the slopes (x)from there. to check insert 0 as one variable to see what other is then repeat

2007-01-24 22:13:16 · answer #4 · answered by wesnaw1 5 · 0 0

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