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okay so we have two equations x+y=0 and 3x-2y=10

how would you solve that then graph

directions read Solve by graphing then check algebraically

we have to give a point like ( 0, 0 ) then graph them


EXAMPLE:

x+y=4
2x-y=5

and the answer is 3,1

2007-01-24 13:44:32 · 5 answers · asked by Nate K 2 in Science & Mathematics Mathematics

5 answers

x+y=0 and 3x-2y=10

ok to solve this you have the two unknown variables and two equations. lets pick one variable and solve for it...how about x:
x + y = 0
x = -y

Now that we know x, plug it into the other equation:
3x-2y=10
3( -y ) -2y = 10
-5y = 10
y = -2

ok now we have a number for y so lets use it with what we know about x:

x = -y
x = 2

so your point is (2,-2)

oh and for graphing, just draw the two lines from your original equations:
x+y=0
y = -x <-- this is the line equation to graph

3x-2y=10
-2y = 10 -3x
y = -5 + 3/2x
y = (3/2)x - 5 <--- this is the other line equation to graph

where these lines intersect will be the point you found above.

2007-01-24 13:50:18 · answer #1 · answered by mdigitale 7 · 0 0

Graphing, them in standard form if you know how or slope-int form. The solution is where the lines intersect.

x + y =0
3x - 2y = 10

By substitution
x + y = 0, so x = -y
Substitute into 2nd equation
3 (-y) - 2y = 10
-3y - 2y = 10
-5y = 10
y = -2,
Then back into first equation
x + -2 = 0,
x = 2

2007-01-24 13:51:56 · answer #2 · answered by leo 6 · 0 0

well first u want to get it in slope intercept form which is y=mx+b m is supposed to be the slope and b the y intercept in other words its going to be on the y axis and according to the slope u go somany spaces up or dow and to the sides so for example
x+y=4 in slope intercept form it would be y= -x+4 the slope is 1 over 1 and the y intercept is 4 so u graph 4 and from that spot u go up once and to the right side once and there u've graphed it hope this helps! :)

2007-01-24 13:54:25 · answer #3 · answered by =D 2 · 0 0

for those two graphs, I'd make them equal each other.

so say y = 4 - x
and
y = 2x - 5

then go

4 - x = 2x - 5

solve for x

x = 3

and then plug that answer into one of your equations

(3) + y = 4

solver for y

y = 1

therefore ---> (3,1)

Checking algerbraically means, putting these values into the x and y's of both equations and seeing if it's true.

solve by graphing, graph both equations on your calculator and find the intercept between the two, it should be (3,1)

2007-01-24 13:52:47 · answer #4 · answered by Kipper to the CUP! 6 · 0 0

..

2016-05-24 06:08:53 · answer #5 · answered by Anonymous · 0 0

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