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The regular season for professional baseball is 162 games. A player was at bat 3 times in each game, and he played in two-thirds of the games.
A:How many times was the player at bat during the season?
B:The player hit 0.250, which means he got a hit 25% of the time, or once in every four at bats. How many hits did he get during the year?

Thanks for helping me out!

2007-01-24 13:43:19 · 6 answers · asked by Anonymous in Science & Mathematics Mathematics

6 answers

(2/3) * 162 = 108 games played
108 * 3 = 324 at bats
324 / 4 = 81 base hits.

2007-01-24 13:47:10 · answer #1 · answered by Michael Dino C 4 · 0 0

Ok,
162 games, played 2/3, so 162 * (2/3) = 108 games
A He has 3 bats per game so 324 bats
B 324 * (1/4) = 81 hits

2007-01-24 21:48:30 · answer #2 · answered by leo 6 · 0 0

162/3=54
54*2=108 (games)
108*3=324 (times at bat)
324/4=81 hits

2007-01-24 21:49:00 · answer #3 · answered by Katie B 3 · 0 0

162 games * 3 times per game = 486 times at bat per season
Since he only played in 2/3 of the games: 486 * 2/3 = 324 times at bat

324 * 0.25 = 81 hits

2007-01-24 21:47:11 · answer #4 · answered by mdigitale 7 · 0 0

a)
Working out:
162/3= 54 (divide by third)
54x2= 108 (multiply by two)
108x3= 324 (multiply by three)

Answer: 324

b)
Working out:
324/4=81 (divide by four)

Answer: 81

I hope I can be of some assistance!

2007-01-24 21:53:50 · answer #5 · answered by Anonymous · 0 0

A: 324
B: 81

2007-01-24 21:48:01 · answer #6 · answered by yungpuller 1 · 0 0

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