anybody who knows algebra 1 really well.... please help!!!!?

Question

i really need help with this algebra stuff! It's making my brain hurt. anyways here is the equation:
10y-1.3=4.7

(by the way thisis SOLVING EQUATIONS AND INEQUALITIES WITH ABSOLUTE VALUE)
thanks! ♥

Answer 1

10y-1.3=4.7
add 1.3 to each side
10y=6
divide each side by 10 and reduce
y=3/5

You don't need to use an absolute value. I must be really old and rusty cause this was simple, must be doing something wrong.

Answer 2

It is 6/10

10y-1.3=4.7
10y-1.3+1.3=4.7+1.3
10y=6
10y/10=6/10
y=6/10

Answer 3

It's not too hard, just go backwards:
10y-1.3=4.7
+1.3 +1.3
10y= 6.0
/10 /10
y = 0.6

Answer 4

10y - 1.3 = 4.7
10y - 1.3 + 1.3 = 4.7 + 1.3
10y = 6
10y/10 = 6/10
y = .6

Answer 5

You have to isolate the variable on one side, the numbers on the other.

You would add 1.3 to each side, taking away the 1.3 on the left and making the 4.7 on the right a 6.

Then, divide each side by 10.

.6

IM me if you ever have any questions.

Answer 6

10y -1.3 = 4.7
first add 1.3 to both sides of the equation
10y = 6.0
divide by 10
y = 0.6
for absolute value y = |0.6| (or 0.6, -0.6)

Answer 7

add 1.3 to both sides
10y=6
divide both sides by 10
y=6/10
y=0.6

Answer 8

10y - 1.3 = 4.7
10y = 6
y = 6/10
y = 0.6

cheers

Answer 9

.6 or 3/5

Answer 10

Definitely 0.6.
10y-1.3=4.7
10y=6 (4.7+1.3-6)
y=0.6 (6/10= 0.6)