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It says there may be more than one answer THANK YOU for any help, I am very frustrated

2007-01-24 11:16:37 · 7 answers · asked by omgpwnedlol32 1 in Education & Reference Homework Help

Also if you answer it please explain how you did it like show the steps if you have time thanks I could really use the help.

2007-01-24 11:22:20 · update #1

Okay, I am understanding it now all up until the part where you have x^2-3X+2=0 I need to know how you get from there to (x-1) and (x-2) could somebody please help me out? I might sound like an idiot but I am doing really bad in this class and I need major help lol

2007-01-24 12:06:39 · update #2

7 answers

Multiple out both sides of the equation:

3x^2 +3x + 6x + 6 = 18x

Simplify:

3x^2 + 9x +6 = 18x

3x^2 -9x +6 = 0

Now factor!

3(x^2 -3x + 2) = 0

3(x-2)(x-1) = 0

You're multiplying 3 times (x-2) times (x -1) and you're getting zero. That's what that equation says. So how do you multiply stuff together and get zero? One of them has to equal zero. Either x-2 = 0 or x - 1 = 0. So X is either 2 or 1.

2007-01-24 11:31:09 · answer #1 · answered by josh c 1 · 0 0

To solve this you need to first use FOIL (first outer inner last) which means 3x*x then 3x*1 then 6*x then 6*1 so you end up with
3x^2 (3 x squared) + 3x + 6x + 6 = 18x
3x^2 +9x +6 =18x

3x^2 -9x +6 = 0

you can divide both sides by 3 and get

x^2 - 3x + 2=0
since 2 is positive the only possible solutions are (X+a) (X+b) or
(x-a) (x-b)
the factors to get 2 are 1, 2

so if you try x+1 and x+2 then when multiplied out you get a +3x term, so that won't work
if you try x-1 and x-2 then you get x^2 -3x +2 which is correct.

you then can solve each x-1=0 so x=1
and x-3=0 so x=3

As a check, put those values back into the original equation and make sure it works
Hope this helps

2007-01-24 11:43:49 · answer #2 · answered by tinman97prn 7 · 0 1

Looking at the formula, first realize you will be multiplying 3x with x, so you will end up with x^2 (X squared) term.

Use FOIL method and remove the bracket on the left side first.
3x^2 + 3x + 6x + 6 then simply it to get:
3x^2 + 9x + 6

Now multiply the right side to get:
(2x)(9) = 18x

Combine them both and get:
3x^2 + 9x + 6 = 18x

Now, put everything on the left side and get:
3x^2 + 9x - 18x + 6 = 0 remember the sign must change from 18x to -18x when it cross the equal sign.

This simplifies to:
3x^2 - 9x + 6 = 0

Factor the above equation.

Now solve this binomial
(3x -6)(x-1)=0

This means
3x-6 = 0
3x=6
x=2

also means
x-1=0
x=1

Therefore, your answer is x=2 and x=-1

They key to solving these is just practice. If you do enough of them, you'll start to see the patterns.

2007-01-24 11:29:32 · answer #3 · answered by tkquestion 7 · 0 0

(3x + 6)(x + 1) = (2x)(9)
3x^2 +3x + 6x + 6 = 18x
3x^2 +9x + 6 = 18x
3x^2 +9x + 6 - 9x = 18x -9x
3x^2 + 6 = 9x
3x^2 + 6/3 = 9x/3
x^2 + 2 = 3x
x^2 + 2/x = 3x/x
x +2/x = 3
1/x + 2/x = 3
3/x = 3
3/x(x) =3(x)
3 = 3x
3/3 = 3x/3
1 = x

2007-01-24 11:36:07 · answer #4 · answered by Anonymous · 0 1

when you simplify it, you get 3x squared - 9x +6=0. By using the quadratic formula, your two answers are x=2, and x=1

2007-01-24 11:24:39 · answer #5 · answered by Jessica 3 · 0 0

1: 3x(x+1)=3x(x)+3x(1)=3xx+3x
2: 6(x+1)=6(x)+6(1)=6x+6
3: 3xx+3x+6x+6=3xx+9x+6

2007-01-24 11:28:21 · answer #6 · answered by martijn 1 · 0 0

well using foil (first - outer - inner - last):
(3x+6)(x+1) becomes
3x(squared) + 3x + 6x + 6 which equals
3x(squared) + 9x + 6

I really have no idea what to do with the (2x)(9) ???, sorry but I hope wat I did say can help...

2007-01-24 11:29:01 · answer #7 · answered by devil4ever731 2 · 0 0

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