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A ferris whell with a radius of 9.5m rotates at a constant rate, copmpleting one revolution every 32 s. What is the direction and magnitude of a passegner's acceleration when (a) at the top and (b) at the bottom.

2007-01-24 10:19:11 · 2 answers · asked by bluevolleyball12 1 in Science & Mathematics Physics

2 answers

First you calculate angular velocity w. It is 2*pi (3.1416)/32 sec

An object revolving at w has a centripetal acceleraton a = r w2 (r * w*w)

At the top, the passenger experiences gravity "g" and the centripetal accel pointing down, so net accel = g + a (pointing down)

At the bottom, the centripetal accel is pointing up but gravity is still down, so net accel = g -a (pointing down)

2007-01-24 11:13:07 · answer #1 · answered by Sir Richard 5 · 0 0

You will need to describe a rotational vector. If you need a formula, check your text, or the Internet. Should be a simple plug and play.

2007-01-24 18:41:09 · answer #2 · answered by Anonymous · 0 0

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