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and an intital kinetic energy of
1.98 × 103 kJ. What is the muzzle velocity of the tank's gun (m/s2) ?



The density of uranium is 18.95 g/cm3

2007-01-24 08:33:25 · 2 answers · asked by Anonymous in Science & Mathematics Physics

it's 1.98 x 10^3

2007-01-24 08:33:59 · update #1

2 answers

Kinetic energy = (1/2)(mass)(velocity^2)

Do the unit conversions to make sure your units are consistent and plug and chug.

2007-01-24 09:15:04 · answer #1 · answered by Bigsky_52 6 · 0 0

K = (1/2)mv^2 = (1/2)ρVv^2
v = √(2K/(ρV))
v = √(2(1.98 × 10^33 kg-m^2/s^2)/((18.95 g/cm3)(322.10 cm3)(1 kg/1,000 g)))
v = √(2(1.98 × 10^6 m^2/s^2)/((18.95)(322.10)))
v ≈ 482.68 m/s for the projectile described and the energy given.

2007-01-24 09:22:42 · answer #2 · answered by Helmut 7 · 0 0

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