A particle moves from rest in a straight line with constant acceleration. After 5 seconds it has travelled 50 m. Find:
(a) the magnitude of the constant acceleration
What is this actually asking??? Does it want me to find the acceleration? Or does the magnitude mean i need to find something else?? Please help... cheers.
2007-01-24 06:29:35 · 3 answers · asked by Anonymous in Education & Reference ➔ Homework Help
Acceleration is a vector quantity so really you should be finding the magnitude and direction. But in this case all they want is the magnitude which is the numerical value of the acceleration
d=1/2at^2+ut
50=1/2a(5^2)
a=4 m/sec^2
2007-01-24 06:36:41 · answer #1 · answered by Glenn T 3 · 0⤊ 0⤋
For particle P, distance moved, S=(20+30t)t For particle Q, distance moved, S = (30t) with a view to fulfill, S for Q would be greater effective than S for P by skill of 20m so, 30t + 20> 20t + 30t^2 30t^2 - 10t - 20 < 0 3t^2 - t - 2 <0 (3t +2)(t -a million)<0 t> a million s As such, debris will collide
2016-11-26 23:30:57 · answer #2 · answered by cosen 4 · 0⤊ 0⤋
hey this is no help at all but i just thought id express my intense dislike for mechanics - rubbish isnt it! ive got stuck on my homework too, everyone else finds it easy but i find it really hard. glad to know im not the only one!
good luck
2007-01-24 08:11:05 · answer #3 · answered by coy carp 3 · 0⤊ 0⤋