Brandon left Miami & drove at a speed of 30kph. Eric left 3 hours later & drove at a speed of 40 kph.
2007-01-24 03:41:13 · 7 answers · asked by Bree 1 in Science & Mathematics ➔ Mathematics
if they are driving with constant speeds you can use the formula for position x = v*t where v is speed and t time
and find out when their positions equal to each other
for Brendon you have x = 30*t, for Eric you
have x = 40*(t-3)
30t = 40(t-3)
30t = 40t - 120
t = 12 h- that's the time B. spent driving before Eric caught up with him
so Eric will need 12- 3 = 9 hours
2007-01-24 03:52:23 · answer #1 · answered by Anonymous · 0⤊ 0⤋
At the three-hour mark (The start of Eric's travel), Brandon is 90 miles ahead.
30 mi/hr * 3 hrs = 90 miles
In 12 hours (9 hours after Eric starts), they will be tied.
2007-01-24 11:54:15 · answer #2 · answered by thubanconsulting 3 · 0⤊ 0⤋
3 hours
2007-01-24 11:44:21 · answer #3 · answered by Chris C 3 · 0⤊ 0⤋
9 hours
2007-01-24 11:44:26 · answer #4 · answered by toneland 2 · 0⤊ 0⤋
40t = 30(t+3) = 30t + 90
10t = 90
t = 9
2007-01-24 11:45:26 · answer #5 · answered by gebobs 6 · 0⤊ 0⤋
9 hours, unless he get pulled over for speeding (or has to stop and pee)
2007-01-24 11:45:01 · answer #6 · answered by muskrat_h8r 2 · 0⤊ 0⤋
hey i like a guy named eric who is also my EX-bf !! ! kekhehehehe welp i have no clue
2007-01-24 11:48:22 · answer #7 · answered by Jay-j 1 · 0⤊ 1⤋