A jet airplane travelling at the speed of 500km/hr ejects its products of combustion at the speed of 1500km/hr relative to the jet plane. What is the speed of the latter with respect to an observer on the ground?
2007-01-24 02:40:07 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Physics
The velocity of the waste products is in the opposite direction to the velocity of the jet, so the velocity relative to the frame of reference of the ground is 1500-500=1000 KM/hr in the direction opposite to the jet.
2007-01-24 02:47:55 · answer #1 · answered by Rich D 3 · 0⤊ 0⤋
let the aeroplane is flying ahead with a speed of 500km/hr
As the speed of products of combustion is 1500km/hr w.r.t.jet plane and obviously the product of combustion are moving in the opposite direction
Therefore the speed of product of combustion w.r.t. an observer on the ground is given by
v=(1500-500)km/hr
=1000km/hr
2007-01-24 03:09:25 · answer #2 · answered by niti 2 · 0⤊ 0⤋
2000 km/hr
2007-01-24 02:43:50 · answer #3 · answered by gansta 2 · 0⤊ 0⤋
You failed to mention the angle of view from said on ground and the distance from of said on ground.Hard to say when you put it that way...
2007-01-24 02:46:48 · answer #4 · answered by Anonymous · 0⤊ 0⤋
1000 km/hr....briefly.
2007-01-24 02:43:57 · answer #5 · answered by bradxschuman 6 · 0⤊ 0⤋