A car with a mass of 2200 kg can accelerate from 0 to 30 m/s in 6 sec.?

Question

assuming all of the force generated by the engine goes into acceleration of the car how much force is the engine producing?

Answer 1

you will find the answer in mechanic books, its easy

Answer 2

Remember Newton's second law? That is, force is equal to mass times acceleration:
F = m*a
now, assuming that the rate of acceleration is constant, (not always true with cars) since the car accelerated 30 m/s in 6s, then the average acceleration a = 30 (m/s) / 6s = 5 m/s/s.
now we know what "m" is, and we know what "a" is, so it's just a matter of plugging the numbers into the equation, I'll let you do that.

Answer 3

The Force generated is given by the equation
F = m * a
where F = Force (in kg m / sq. sec)
m = mass of the accelarating body (in kg)
a = acceleration (in m /sq. sec) which is in turn given by the equaton
a = (v - u) / t
where v = final velocity (in m /sec)
u = initial velocity (in m / sec)
t = time (in sec)

Thus, the answer to your problem
given values
v = 30 m/s
u = 0 m/s
t = 6 sec.
m = 2200 kg

it gives

a = 6 m / sq. sec
and
F = 11,000 kg m / sq. sec

This solves the problem.

Answer 4

properly, F = m * a or positioned yet differently F = d(mv)/dt - or fee of exchange of momentum. because of the fact the motor vehicle starts table certain, each and all of the momentum it has is generated as a effect of the engine. d(mv)/dt = m * v / t = 2200 * 30 / 6 = 11000N

Answer 5

v = at (velocity = acceleration * time)
a = v/t
a = 30 / 6
a = 5m/s^2

F = m * a
F = 2200kg * 5m/s^2
F = 11000N