there is 1question?

Question

A RECTANGULAR FIELD HAS 80M LENGTH AND 48M BREADTH.Three roads,each of width 2m pass through the field such that two roads are parallel to the breadthand the third road parellel to the length.Find the area covered by the three roads?

Answer 1

.

Area of a rectangle = length * breadth

For the area of the 2 roads ||el to the breadth

Area = 2 [ 48 * 2 ]
Area = 192 sq. m

For the area of the road ||el to the length

Area = [ 80 * 2 ]
Area = 160 sq. m

So, the total area of the 3 roads = 192 + 160 = 352 sq. m

But these roads will intersect forming 2 squares of 2m x 2m dimensions of area 4 sq. m each

So, the total area actually covered by the roads
= 352 - (2*4) = 344 sq. m

.

Answer 2

First let us calculate the area of the road parallel to the length.
That would be = 80 * 2 = 160

Now let us do the same with one of the roads parallel to the breadth.
That would be = 48 * 2 = 96

Now since the two roads intersect, the are covered by the road parallel to the breadth would be less by the are covered in the intersection.
That would be = 2 * 2 = 4

The actual area covered by the road running parallel to the breadth without considering the area of intersection would be = 96 - 4 = 92

Since there are 2 such roads, the total area covered by the roads would be = 160 + 92 + 92 = 344 M^2

:-)

Answer 3

Area of two roads passing parallel to the breadth = 48*2 = 96 m sq
area of one road parellel to the length = 2* 80 = 160

but a 8 m sq has been cut because both of the roads take that so

160+96-8=248 m sq

Answer 4

The two roads parallel to the breadth cover each 2*48=96m^2
The third road should cover 2*80=160m^2 if alone
From the total subtract the intersections because they are included each twice. Each is 2*2=4m^2
Total area = 2 * 96 + 160 - 2 * 4 = 344m^2

Answer 5

The two roads parallel to the breadth cover each 2*48=98m^2; the third road covers 2*80=160m^2-2*(4)=152m^2--where the subtraction is due to the intersection of the roads. Therefore, in all the roads cover 98+98+152=348m^2.

Answer 6

From information that you have provided, its too difficult to answer without knowing whether the three intersecting roads form a closed sturcture and if they do where exactly do they intersect each other. Assuming that they do form a closed structure at any one side of rectangular field and roads joining each other at thier end points the area would be 4sqm.

Answer 7

the area of the road is
2*48*2+2*80=
=192+160=
=352
however,there is 2 overlapped areas of which each is 2*2=4

so the total area of road is 352-4=348sq.m

Answer 8

2*48*2+80*2-2*2*2
=192+160-8 = 344 m^2

Answer 9

It is 344 Sq Mt rs.

Answer 10

344 sq. meter.