Please help me answer this specific heat problem!!!?

1 ⤊

A tank containing 5 kg of H20 at 90 celcius cools down to 20 celcius. How much heat does the water loose?

2007-01-24 00:18:37 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

Given:
5 kg-M H20
90 C-Ti
20 C Tf
q=c.m.delta T
=(1 cal/g deg C)(5 kg)(20-90)
=(1 cal/g C)(5000g)(-70 C)
= - 350,000cal

2007-01-24 00:49:23 · answer #1 · answered by Tin 3 · 1⤊ 0⤋

1470 KJ

2007-01-24 08:23:06 · answer #2 · answered by Kaku 1 · 0⤊ 0⤋

dQ=mCdT
dQ=5*4200*(90-20)
dQ=5*4200*70
=5*42*7000
dQ=147000 j

2007-01-24 08:27:23 · answer #3 · answered by miinii 3 · 0⤊ 0⤋

ino no

2007-01-24 08:26:28 · answer #4 · answered by Kwadwo B 4 · 0⤊ 1⤋