What is the integral of 1/(3+x^2)?

How do you do that? thanks!

2007-01-24 00:13:20 · 2 answers · asked by ben_ev0lent 1 in Science & Mathematics ➔ Mathematics

Tan^-1(x/sqrt(3))/(sqrt(3))

I used the integral:
dx/(a^2 + bx^2) = (1/ab)*arctan(bx/a +c)
a=sqrt(3)
b=1

2007-01-24 00:20:30 · answer #1 · answered by yhwhlivesinme 2 · 0⤊ 0⤋

ASNWER IS 2...DO YOUR OWN HOMEWORK

2007-01-24 08:20:31 · answer #2 · answered by the man 3 · 0⤊ 1⤋

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