2007-01-23 23:37:17 · 9 answers · asked by varun 1 in Science & Mathematics ➔ Mathematics
Hate to borrow this line from "Little Man Tate" but all numbers are multipliers of 11.
2007-01-23 23:45:34 · answer #1 · answered by Pretty_Bad_Logic 3 · 0⤊ 1⤋
firstly add the numbers at odd places. let it comes out to be A
then add the numbers at even places. let it comes out to be B
Then operate |A-B| and see if the difference is 0 or 11 then the whole number is a multiple of 11
For example:- 233436821409 is a number
To check whether it is a multiple of 11
firstly add numbers at odd places i.e.
A= 2+3+3+8+1+0=17
B= 3+4+6+2+4+9= 28
Then the difference i.e |A-B|=28-17=11
Hence it is a multiple of 11
2007-01-24 11:39:33 · answer #2 · answered by niti 2 · 0⤊ 0⤋
You can recognize those numbers by the following
Suppose number is AnAn-1...A2A1
then what you have to do is to calculate
A1-A2+A3-A4...
that is, the subtraction the sum of odd nth numbers and the sum of even nth numbers must be divide into 11
ex.591713078
8-7+0-3+1-7+1-9+5=-11
so this number is the multiplier of 11
2007-01-24 10:30:07 · answer #3 · answered by happyrabbit 2 · 0⤊ 0⤋
Starting from the last digit sum up the digits on odd places .Also sum up the digits on even places.
Substact both and if the result is 0 or multiple of 11 ,11 is a divider.
Ex 7953 IIIII (3+9)-(7+5)=0 7953=11*723
2007-01-24 07:49:31 · answer #4 · answered by santmann2002 7 · 1⤊ 0⤋
Hey, I'm in Sec 1 now, but I know how to do this using test of divisibility.
1st, add the numbers in the odd places. example:
5148
5 and 4 are in the odd places. so we add them tgt. 5+4=9
then we add the numbers in the even places.
1+8=9
so we subtract them.
then if the answer is 0 or a multiple of eleven, the number is dividable by eleven!
Hope that helps! I did the best I could! Good luck in your future endeavours!
2007-01-24 07:58:13 · answer #5 · answered by Misumi Nagisa fan xD 2 · 1⤊ 0⤋
is it that you mean 'how to test if a number has 11 as a multiplier', cause every number can be a multiplier for every other number.
2007-01-24 07:48:29 · answer #6 · answered by Anonymous · 0⤊ 1⤋
add alternate number as 11,121,1331
two groups of alternate number are 1,1
1&1,2
1&3,3&1
addition of these two groups will be always equal
2007-01-28 06:35:11 · answer #7 · answered by bankeybiharimehrotra 1 · 0⤊ 0⤋
multiply
2007-01-24 07:41:07 · answer #8 · answered by Indu g 1 · 0⤊ 1⤋
college ayega to mein samjha dunga waise .. yeh sab kya hai ..
2007-01-24 08:53:50 · answer #9 · answered by dodo 1 · 0⤊ 1⤋