math help please i am stumped.?

Question

rewrite the middle term as the sum of 2 terms and then factor completely.

1.) 12w^2+19w+4
2.) 4z^3-18z^2-10z

please hep me I am lost so badly

2.) 4z

Answer 1

12w^2 + (16w + 3w) + 4
(12w^2 + 16w) + (3w + 4)
4w(3w + 4) + (3w +4)
(3w+4)(4w + 1)
---------------------
4z^3 - 18z^2 - 10z
2z(2z^2 - 9z - 10)
2z(2z^2 - 10z + z - 5)
2z[2z(z-5) + (z-5)]
2z(2z+1)(z-5)

Answer 2

12w^2+19w+4=0
(4w+1)(3w+4)=0
(4w+1)=0 or (3w+4)=0
w= -1/4 or -4/3

4z^3-18z^2-10z=0
(2z^2+1)(2z-10)=0
(2z^2+1)=0 or (2z-10)=0
2z^2=-1 or 2z=10
z^2=-1/2 or z=5
z=square root of -1/2 is impossible so, z=5
This is the closest answer i can get.
or
4z^3-18z^2-10z
2z(2z^2-9z-5)=0
2z=0 or (2z+1)(z-5)=0
z=0 or z=-1/2 or 5
Last minute thought-could this be the correct answer.

Answer 3

1.) 12w^2+19w+4 = 12 w^2 +16w +3w +4 =4w(3w+4) +1(3w+4)
= (4w+1)(3w+4)Answer.
2.) 4z^3-18z^2-10z =2z(2z^2 -9z -5)=2z (2z^2 - 10z +1z -5)
= 2z[2z(z-5)+1(z-5)=2z(z-5)(2z+1) Answer

Answer 4

Problem 1

12w² + 19w + 4

12w² + 3w + 16w + 4

3w(4w + 1) + 4(4w + 1)

(3w + 4)(4w + 1)

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Answer 5

write it well then if you need help