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factor the trinomials completely

1...x^2-11x-60

2...use the ac test to determine which trinoamil can be factored. Find the values of m and n of those that can be factored.
x^2+2x-15
and
x^2-3x+7

2007-01-23 21:35:16 · 8 answers · asked by Anonymous in Science & Mathematics Mathematics

8 answers

x² - 11x - 60

x² - 15x + 4x - 60

x(x - 15) + 4(x - 15)

(x + 4(x - 15)

- - - - - - - - - - -

x² + 2x - 15

x² + 5x - 3x - 15

x(x + 5) - 3(x + 5)

(x - 3)(x + 5)

- - - - - - - -

x² - 3x + 7

Cannot be factored. Use the Quadratic formula

- - - - - - - -- -s-

2007-01-24 02:06:42 · answer #1 · answered by SAMUEL D 7 · 0 0

Putting x^2-11x -60=0 the roots are 15 and -4 so it can be factored into (x-15)*(x+4)

2) x^2+2x-15 2^2-4*(-15)= 4+60 =64 >0 and it Can be factored into (x+5)(x-3)

3) x^2 -3x+7 (-3)^2 -4*7 = -19 <0 so it can´t be factored

2007-01-23 21:46:25 · answer #2 · answered by santmann2002 7 · 0 0

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2016-05-24 03:41:34 · answer #3 · answered by Anonymous · 0 0

I know that the first part can be factored as (x-15)(x+4), but I'm not sure what the ac test is or what the m and n values refer to. Sorry!

Good luck!

2007-01-23 21:46:27 · answer #4 · answered by tiggywinkle 3 · 0 0

For the first one, find two numbers which when multiplied together give you -60 and when added together give you -11.

umm.....

15 and 4 give 60 when multiplied.
+15 and -4 give -60 when multiplied, but when added give +11
-15 and +4 give -60 when multiplied, and give -11 when added.

So write this as:

x² -15x + 4x + (-15*4)

It should be easy to factorise then.

Never heard of the ac test, sorry.

2007-01-23 21:49:02 · answer #5 · answered by Gnomon 6 · 0 0

x^2-11x-60=0
(x-15)(x+4)=0
(x-15)=0 or (x+4)=0
x=15 or -4 (answer)

x^2+2x-15=0
(x+5)(x-3)=0
(x+5)=0 or (x-3)=0
x=-5 or 3

x^2-3x+7=0 --??????????

2007-01-23 21:51:44 · answer #6 · answered by Anonymous · 0 0

1)
x^2-11x-60
=(x+4)(x-15)

2)
x²+2x-15
a=1,b=2,c=-15
2²-4(1)(-15)=64(Can be factored)

x²-3x+7
a=1,b=-3,c=7
(-3)²-4(1)(7)= -19(0>,so can't)

2007-01-23 21:46:13 · answer #7 · answered by A 150 Days Of Flood 4 · 0 0

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2007-01-23 21:54:51 · answer #8 · answered by Anonymous · 0 1

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