help me please.?

Question

Solve this equations. Be sure to check your solutions.

sqrt(4x+1) +3=0

Answer 1

The people answering 2 are absolute wrong

if it was 2, plug it in

sqrt(4*2+1)+3=0
sqrt(8+1)+3=0
sqrt(9)+3=0
3+3 = 0 not true

There is no real solution
sqrt(4x+1) = -3

Answer 2

sqrt(4x+1) = -3 Subtract three from both sides
4x+1 = 9 Square both sides to get rid of the root
4x = 8 Subtract one to leave the factor by itself
x = 2 Divide by 4 on both sides to determine the value of x

Answer 3

You have,
sqrt(4x+1) +3=0
So,
sqrt(4x+1) = -3

Squaring both sides,
4x +1 =9
4x = 8
x =2
Hence the solution is x=2

And there is no case of any negative root, only this answer will come as we are squaring both sides and not taking the
underroot.

Answer 4

sqrt(4x+1)=-3
sq. both sides
4x+1=9
4x=9-1
x=8/4
x=2

Answer 5

√[4x+1] = -3
4x + 1 = 9
4x = 8
x = 2

This works if you take the negative root only.

NOTE: √9 = ±3: 3 * 3 = 9, (-3) * (-3) = 9

Both Mathcad and Excel Solver give the solution as x = 2

Answer 6

The square root of any number can only be positive. (Positive x Positive = Positive, Negative x Negative = Positive, only Negative x Positive = Negative.) Since, no positive number plus 3 can equal 0, the equasion is invalid. It does not matter what 4x + 1 is equal to, because its square root is positive. There is no correct answer.

Answer 7

This has no real solution.

But it probably has a complex solution. I'm too drunk and too tired to solve it for you, but I'll tell you how to approach it. Replace the real variable x by the complex variable Z= a+ib, where
i= sqrt(-1).
This gives you:
(5a +_4bi)^(1/2) = -3

Use Euler's Identity:
e^(ix) = cosx + isin(x)

This should yield a complex solution for z.

Answer 8

short and simple. x=2