prove that each statements is true for all natural numbers n, in using the principle of mathematical induction

Question

1.) 1+3+5...+(2n-1)=n squared
2.) 1(2)+3(4)+5(6)+...+(2n-1)(2n)=n(n+1)(4n-1) over 3
3.) 1+4+7+...+(3n-2)=n(3n-1) over 2
4.) 7+13+19+...+(6n)+1)=n(3n+4)
5.) 2+6+18+...+2(3 to the power of n-1)=(3 to the power of n)-1
6.) 4+10+18+...+n(n+3)=n(n+1)(n+5) over 3

Answer 1

Come on...

Answer 2

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Answer 3

Why don't you try at a solution, and we'll tell you if you're on the right track.

Good luck.

Answer 4

I would have to say................

DO YOUR OWN HOMEWORK AND MAYBE YOU'LL LEARN SOMETHING!

John