i need to know if ashton kutcher and bruce willis have ever been or are going to be in a movie together. please get back with me soon if you know. thanks
2007-01-23 16:44:28 · 15 answers · asked by Anonymous in Entertainment & Music ➔ Celebrities
Maybe a home movie with Demi. Seriously i did hear some where that they are going to be but don't know if it's happened or not.
2007-01-23 16:48:14 · answer #1 · answered by Anonymous · 0⤊ 0⤋
No, they have not. I just checked the whole filmography of Bruce Willis. He has never done a film with Kutcher. He has a few films that are to be released this year (2007). The coolest is that there is to be another 'Die Hard' movie.
I never knew that he could really play Harmonica. That his appearance on 'Friends' was for free because of a bet that he lost, or that he used to be a bouncer.
Finding answers to some of these questions are pretty cool.
2007-01-23 17:23:55 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Bruce appeared on the 70's show with Ashton!!! So I definitely could see them doing a movie together.
2007-01-23 16:48:24 · answer #3 · answered by Tammers 4 · 0⤊ 0⤋
no but they have gone to movie premiers with demi and the kids together, they don't have a problem with each other at all
2007-01-23 16:47:11 · answer #4 · answered by Anonymous · 0⤊ 0⤋
no it's doubtful other than demi they don't seem to run in the same circles or do the same type of movies.
2007-01-23 18:14:49 · answer #5 · answered by Anonymous · 0⤊ 0⤋
not that i know of.. and i am a movie buff.. but am not sure to be honest.. not 100%
2007-01-23 16:56:32 · answer #6 · answered by Anonymous · 0⤊ 0⤋
No. Check imdb.com
2007-01-23 16:48:31 · answer #7 · answered by Christina 5 · 0⤊ 0⤋
I doubt they would star in one togethor - that would just be too corny.
2007-01-23 17:24:23 · answer #8 · answered by Kylie 6 · 0⤊ 0⤋
Wish i could help, but not that i know of.
2007-01-23 16:47:29 · answer #9 · answered by queendebadow 5 · 0⤊ 0⤋
not other than their home movies
2007-01-23 17:33:41 · answer #10 · answered by Katprsn 5 · 0⤊ 0⤋