A ball is thrown upward with an initial velocity of 14 m/s. Using the approximate value of g = 10 m/s2, what are the magnitude of the ball's velocity at the following times?
(a) 1.05 s after it is thrown upward?
m/s
(b) 2.05 s after it is thrown downward?
m/s
2007-01-23 16:15:09 · 3 answers · asked by bibun 2 in Science & Mathematics ➔ Physics
(a) 14-1.05*10=3.5 m/s
(b) -14-2.05*10=-34.5
2007-01-23 16:28:43 · answer #1 · answered by bruinfan 7 · 0⤊ 0⤋
Not wanting to do your homework for you, you should use the equation v = u + at, where v is the velocity at a given time, u is the initial velocity, a is the acceleration due to gravity (which will be negative 10, since it is being thrown against gravity), and t is the time you are interested in.
If the ball is thrown downward, as in (b), then "a" will be positive 10, since the initial velocity and gravity are in the same direction.
2007-01-24 00:27:51 · answer #2 · answered by Ben C 2 · 0⤊ 0⤋
a) 24.5 m/s
b)34.5 m/s
not 100% sure if correct but yeah.
BTW, things accelerate through the air at an approximate rate of 9 m/s/s, not 10. so yeah.
2007-01-24 00:22:47 · answer #3 · answered by Hi 1 · 0⤊ 0⤋