Acetylene gas (c2h2) burns in a welding torch with oxygen to form carbon dioxide gas and water vapor
2007-01-23 15:39:35 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Start with a reaction
C2H2 + O2 -> CO2 + H2O
identify reactants and products
Note that each mole acetylene creates 2 mole CO2, so the first alteration is
C2H2 + O2 -> 2 CO2 + H2O
The hydrogen is OK, but the oxygen balance is off. To provide 5 oxygen in products, we need 2-1/2 in the reactant.
C2H2 + 2-1/2 O2 -> 2 CO2+ H2O
Since teachers don't like fractions, we restate this
2 C2H2 + 5 O2 -> 4 CO2 + 2 H2O
If you have done simultaneous equations, you can figure these coefficients that way. If not (what I suspect),
the approach shown is more understandable. Just keep good books!!
2007-01-23 15:51:05 · answer #1 · answered by cattbarf 7 · 0⤊ 0⤋
2 C2H2 (g) + 5 O2 (g) ---> 4 CO2 (g) + 2 H2O (g)
good one... practice makes perfect
2007-01-23 23:49:39 · answer #2 · answered by Some Guy 2 · 0⤊ 0⤋
Sorry michael Carbon does not balance.
2C2H2 + 5O2 ---> 4CO2 + 2H2O
2007-01-23 23:53:09 · answer #3 · answered by Anonymous · 0⤊ 0⤋
2C2H2 + 3O2 --> 2CO2 + 2H20
2007-01-23 23:43:32 · answer #4 · answered by Michael Dino C 4 · 0⤊ 1⤋