Chemistry Question?

Question

How many grams of AgNO3 are in a 35ml beaker of 1.5 M AgNO3?


i need help because i didnt understand it much....if you could also give me some tips in doing stoichiometry......thank you very much.

Answer 1

OK. First of all let’s understand what does 1.5M means. It means there are 1.5 moles of AgNO3 in 1000ml of the solution. So you can work out how many moles of AgNO3 would be in 35ml of this solution.

1000ml of this solution contains 1.5 moles of AgNO3
Therefore 1ml of this solution would contain 0.0015 moles of AgNO3
Therefore 35 ml of this solution would have 0.0525 moles of AgNO3 (0.0015 moles multiplied by 35 )

Now we know that there are 0.0525mloes of silver nitrate in 35 ml beaker. We just need to convert 0.0525 moles into grams. For that we need the molecular mass of AgNO3. I am sure you have a list with elements and their atomic masses. (Try this web link if you don’t have one.
http://en.wikipedia.org/wiki/Atomic_weight)

Approximately Ag has the atomic mass of 108 u
Nitrogen has the atomic mass of 14 u
And Oxygen has the atomic mass of 16 u

So the Molecular Mass of AgNO3 would be 108+14+ (16*3)= 170 u
This means Molar Mass of AgNO3 would be 170 g/mol


This means one mole of AgNO3 has the mass of 170g. But in our 35ml of AgNO3 we have only 0.0525 moles. So we can calculate how much it weighs.

The answer would be 170 g/mol * 0.0525mol = 8.925 g


I’ll give you a good tip for these types of calculations. Learn the meaning of the basic concepts thoroughly….For example, molarity means the amount of moles in 1000ml of the solution. Molar Mass means the mass of one mole of the substance. Once you know what each of these term means, doing this kind of calculations is a breeze and you would be able to reason your answer quickly.

Hope this would help you….Good Luck with your studies

Answer 2

The important relation is:
Moles = Volume x Molarity
Where volume = 0.035 L
Molarity = 1.5
This leads to 0.0524 moles of AgNO3.
I don't have my atomic chart with me, but AgNO3 should be about 150 g/mole..
Then mass AgNO3 = moles x molar weight
So mass AgNO3 = 0.0525 x 150 (appx) = 7.8 grams (appx)

Answer 3

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