What is the molarity of sodium chloride in solution that is 13.0% by mass sodium chloride and that has a density of 1.10 g/mL?
2007-01-23 14:47:46 · 3 answers · asked by Travis S 2 in Science & Mathematics ➔ Chemistry
In 1 l sodium hydroxide solution, there are therefore 1 100 g of which 13 % of that mass is dissolved sodium chloride .... that works out to 143 g.
40 g of sodium hydroxide = 1 mole since Mr of NaCl = 40
Hence 143 g of sodium hydroxide = [143/40] moles
Therefore concentration is [143/40] moles per dm^3
2007-01-23 15:10:51 · answer #1 · answered by pete 2 · 0⤊ 5⤋
M = 1100g/L x 13.0g NaCl/100g soln x 1mol NaCl/58.35g
M =2.45 Molar
Nearly all density and percent composition of solution problems are solved by this method.
M = d x 1000 x%/100 x 1/MM = d x10 x % x 1/MM
MM= molar mass
2007-01-23 15:00:22 · answer #2 · answered by docrider28 4 · 4⤊ 1⤋
NO it is not "C" ITS "D" MOLARITY IS variety of MOLES IN ALITER OF a answer SO DIVIDE the load OF SODIUM CHLORIDE WITH ITS MOLECULAR WEIGHT AND DIVIDE the effect WITH THE variety of LITERS
2016-12-16 12:07:28 · answer #3 · answered by Anonymous · 0⤊ 0⤋