How many atoms of nitrogen are in 7.8 g of aspartame?

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How many atoms of nitrogen are in 7.8 g of aspartame?

2007-01-23 14:26:53 · 2 answers · asked by fabulous101 2 in Science & Mathematics ➔ Biology

2 answers

aspartame is C14 H18 N2 O5
atoms N= (7.8g C14H18N2O5) (1 mol C14H18N2O5/ 294.301g C14H18N2O5) ( 2 mol N / 1 mol C14H18N2O5) ( 6.02X10^23 N atoms / 1 mol N) = 3.2 X 10^21 N Atoms

2007-01-24 15:41:02 · answer #1 · answered by wesnaw1 5 · 0⤊ 0⤋

Well aspartame is C14H18N2O5

So.....

atoms N= (7.8g C14H18N2O5) (1 mol C14H18N2O5/ 294.301g C14H18N2O5) ( 2 mol N / 1 mol C14H18N2O5) ( 6.02X10^23 N atoms / 1 mol N) = 3.2 X 10^21 N Atoms

2007-01-23 15:56:44 · answer #2 · answered by -Eugenious- 3 · 1⤊ 0⤋