joe bob bounces a .10 kg tennis ball off a wall. the ball's initial velocity is 12i - 1.4j meters per second. if the wall exerts a constant force of -185i newtons and the ball's final velocity is -11i - 1.4j meters per second, (a) find the ball's change in momentum. (b) how long was the ball in contact with the wall?
2007-01-23 12:54:26 · 2 answers · asked by argentina_mandy20 1 in Science & Mathematics ➔ Physics
change in momentum =m(vi-vf)
force =d(mv)/dt so plug in momentum change and force and solve for dt
2007-01-23 14:04:35 · answer #1 · answered by meg 7 · 1⤊ 0⤋
damn quick: Impulse-momentum equation: F * t = m * change in speed F = 111,563 N - four hundred N = 111,163 N 111,163 N * 4.1743 sec = 20.418 kg * V 464028 N/s = 20.418 kg * V V = 464028 N/s / 20.418 kg V = 22,726.4 m/s (the Newton is a derived from a kg*m/s^2 so contraptions cancel correct to go away m/s)
2016-12-02 23:27:11 · answer #2 · answered by ? 4 · 0⤊ 0⤋