Just as there's no largest number, there is no hardest math problem. Go to http://www.claymath.org for some hard problems.
If you can solve one of these, you'll get $1 million dollars.
The proving of Fermat's Last Theorem is also a good example of a difficult math problem. It went unproven for over 350 years, untill Andrew Wiles found a proof back in 1995.
2007-01-23 12:56:20
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answer #1
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answered by Andrew 6
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1+1
2007-01-23 12:51:54
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answer #2
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answered by Anonymous
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1+1
2007-01-23 12:46:54
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answer #3
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answered by Anonymous
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the fact that 2+2=5 in large quantities of 2
2007-01-23 12:51:47
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answer #4
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answered by Urmi K 2
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-95 - 864 + .9845 x 164 3/4 + -587 = ?
2007-01-23 12:49:39
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answer #5
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answered by Cartman 3
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There are many. How about, provide me with a procedure for factoring any number in nlogn time.
2007-01-23 12:47:50
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answer #6
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answered by mdigitale 7
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It would probably finding the ending to pi, it has not yet been solved and i think it is 22/7
2007-01-23 12:47:17
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answer #7
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answered by attax321 3
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i read a book titled something like that once, the answer is 1+1
2007-01-23 12:48:06
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answer #8
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answered by Calebs Mummy 5
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I think it boils down to the "singularity" of black holes.
2007-01-23 12:50:23
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answer #9
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answered by inkinyou 1
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647823647832647862341872346872315776247632746372463746732647247823478623746238462374628462374724678364723647823647216472834672364728361876487264872348726472836482713462782647123 x 0
2007-01-23 12:49:47
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answer #10
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answered by Spada 7
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