Determine the number of grams of NH3 produced by the reaction of 3.5g of hydrogen gas with sufficient nitrogen

Question

Determine the number of grams of NH3 produced by the reaction of 3.5g of hydrogen gas with sufficient nitrogen gas.

You must show:

1. The balanced equation. (2 points)

2. Your work showing cancellations. (8 points)

Answer 1

The bal'd eq. : N2 + 3 H2 = 2 NH3
The calculation:
Considering the molar masses of each compound in the eq. above:
2 x 14 + 3 x 2 = 2 x 17 (N is 14; H is 1; NH3 is 17)
28 + 6 = 34
Therefore, the proportion we need to solve our problem is:
3.5 : 6 = x : 34 ; hence, x = 19.8 (g of NH3).

Answer 2

you want to first figure out the balanced equation, that could be: 3H2 + N2 -> 2NH3 Now you want to figure out what percentage moles of H2 gas you've. this will be executed by technique of dividing by technique of the molar mass so the grams of H2 cancel out and also you'll get moles of H2: 3.5 g H2 x a million mol H2/2.0 g H2 = a million.seventy 5 moles H2 Now you want to figure out what percentage moles of NH3 will be created from a million.seventy 5 moles of H2 gas. this will be executed by technique of creating use of the molar ratio between the NH3 and H2 and canceling out moles of H2 to get moles of NH3: a million.seventy 5 moles H2 x 2 moles NH3/3 moles H2 = a million.166 moles NH3 Now that you've moles of NH3, you may figure out what percentage grams that's. You attempt this by technique of multiplying by technique of the molar mass of NH3 so as that the moles cancel out and also you get your answer in grams: a million.166 moles NH3 x 17 grams NH3/a million mol NH3 = 19.80 2 grams NH3 wish that's sensible! those issues continuously seem very overwhelming, yet they develop into extremely user-friendly with practice. merely keep in innovations convert to moles, use molar ratios, and then convert decrease back to grams.