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Which gives the more concentrated solution, stearic acid [CH3(CH2)16COOH] in H2O or CCl4? Explain.

I know this has to do with intermolecular forces which I'm not so good at. I was thinking the answer was in H2O because it could exhibit H bonding and it would be more soluble, however, I was not sure if CCl4 would exhibit Ion-dipole bonding which then would make it the Solvent which would yield a higher concentration.

Is this right? Please tell me which one it is, if CCl4 can exhibit Ion-dipole bonding with stearic acid, and if H2O is not the right answer. Thank you

2007-01-23 10:33:49 · 2 answers · asked by meanest_pianist 2 in Science & Mathematics Chemistry

2 answers

You're right.

Stearic acid will exhibit hydrogen bonding with water. In addition to that water and stearic acid are both very polar molecules whereas carbon tetrachloride (CCl4) is a very non-polar molecule. Polar molecules exhibit more dipole-dipole moments allowing them to exist easier in solution.

2007-01-23 10:41:14 · answer #1 · answered by LGuard332 2 · 0 0

in fact aspects bond jointly to get an entire outer shell, so the variety of bonds is merely how many electrons they could desire to get that. with H2, hydrogen has one electron and it desires one greater (because of the fact it interior the 1st shell) to get an entire outer shell so it purely varieties one covalent bond (a covalent bond is whilst 2 atoms share electrons) With O2, oxygen has 6 electrons in its outer shell it desires 2 greater so it varieties a double bond and with N2, nitrogen is in team 5 and so has 5 outer shell electrons as a result it desires 3 electrons to get an entire outer shell and so varieties a triple bond wish this helps =] !!

2016-11-26 21:56:20 · answer #2 · answered by ? 4 · 0 0

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