for the function f(x)= x^2 - 2x + 1???

Question

find f(0)

solve f(x)=0

graph the function y=f(x)=x^2

WHAT!? i think i got the first two but i dont know the rest. PLEASE HELP!

Answer 1

f(0) = 0^2 -2(0) +1= 1

x^2 -2x +1 = 0

You can factor this one:
(x -1)(x -1) = 0
x - 1 = 0
x = 1

The function would be a parabola (U shaped curve) with a vertex at (0,1). Other points on the graph would be (-2, 9), (-1, 4), (0, 1), (1, 0) and (2, 1).

Answer 2

To find f(0) you plug in 0 for x, so f(0)=0-0+1=1

To find where f(x)=0, solve

x^2 - 2x + 1 = 0

(x-1)^2 = 0

x = 1

Since f(x) = (x-1)^2 (factored) this is an upward-opening parabola with an axis of symmetry of x=1 and a vertex at (1,0) that goes through the point (0,1). That should help you sketch the graph. Plot a couple more points to give you the right shape.

Answer 3

f(0) = 0^2 -2(0) + 1 = 0 - 0 + 1 = 1
Use the quadratic equation on the second one
a = 1, b=2, c =1

y=x^2 is just a parabola opening upwards...graph a few points and connect the dots smoothly

Answer 4

Use a graphing calculator, and graph x^2-2x+1 and graph x^2 and find where they intersect, thats where f(x)=x^2... Im pretty sure thats correct its been awhile since Ive done algebra related stuff.

Answer 5

f(0)= 0^2-2(0) + 1

f(0)= 1

thats basically it