how do I simplify this expression using algebraic simplification?

Question

(n-2)/\3+6(n-2)/\2+12(n-2)+8 How do I simplify this expression using algebraic simplification?

Answer 1

I am going to do this step by step - if you need more help ask.

(n-2)/\3+6(n-2)/\2+12(n-2)+8

(n-2)^3 = (n-2)(n-2)(n-2) --- multiply the first two binomials
(n^2-4n+4)(n-2) --- multiply these now
(n^3-2n^2)

complete next set
6(n-2)^2 = 6(n-2)(n-2) ---- multiply the binomials first
6(n^2-4n+4) ---- multiply through by 6
6n^2-24n+24

complete last set
12(n-2) = 12n-24

pull it all together now -
n^3-2n^2+6n^2-24n+24+12n-24+8

n^3+4n^2+12n+8

I hope this helps!!!!

Check over the math to make sure - you shouldn't always assume that the math is correct - make sure you do the problem as well!

Answer 2

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Answer 3

Remember to follow the order of operations. Start with exponents, then multiply. Now you should be able to add like terms together.