Jaqueline and Gilles were playing with rocks at the edge of a cliff which was 80 m above the beach below. Gilles threw a 1 kg rock upwards with a speed of 30 m/s. Let the acceleration due to gravity be -10 m/s^2.
I've calculated kenetic and potential energy
I need to know how to get the speed and height of the rock after each second that passes by. Any help is greatly appreciated.
2007-01-23 02:49:10 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
create an equation for the speed of the rock and another for the height.
speed=l30-10tl
height=-5t^2+30t+80
time/speed/height
0/30/80
1/20/105
2/10/120
3/0/125
4/10/120
5/20/105
6/30/80
7/40/45
8/50/0
2007-01-23 03:08:00 · answer #1 · answered by Ben B 4 · 0⤊ 0⤋
You do not have to calculate energy.
Speed alters @ -10m/s^2 for the upward journey and 10m/s^2 for downwards.
Use the eqns.
v = u+at
v^2 = u^2 + 2as
2007-01-23 11:06:15 · answer #2 · answered by ag_iitkgp 7 · 1⤊ 0⤋
I agree with the FIRST MAN.
2007-01-23 12:14:32 · answer #3 · answered by Mosh 2 · 0⤊ 0⤋