How many Na atoms of mass 22.99 amu are in 29.99g of sodium ?

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How many Na atoms of mass 22.99 amu are in 29.99g of sodium ?

Please explane this out to me. Thanks for the help =)

2007-01-23 02:47:03 · 3 answers · asked by Heavy Metal 3 in Science & Mathematics ➔ Chemistry

3 answers

first you calculate how many moles of Na you have
29.99/22.99 = 1.304 mole

1 mole contains 6.02 10^23 atoms (Avogadro's number)

and 1.304*6.0210^23 = 7.85 10^23 atoms

2007-01-23 03:06:25 · answer #1 · answered by maussy 7 · 0⤊ 0⤋

1 mole of Na atoms
That's 6.02*10^23 atoms

2007-01-23 10:53:10 · answer #2 · answered by MateoFalcone 4 · 0⤊ 0⤋

(29.99/22.99) x 6.023 x 10^23 = 7.857 x 10^23 atoms.

2007-01-23 10:58:07 · answer #3 · answered by ag_iitkgp 7 · 0⤊ 0⤋