a piece of iron wighing 0.920grams was heated until all the iron was converted to an oxide. if the weight of the oxide is 1.315grams, what is the formula of the oxide?
2007-01-23 02:28:57 · 3 answers · asked by piangpiang 2 in Science & Mathematics ➔ Chemistry
In the oxide, the mass of oxygen is 1.315-0.920 grams, or 0.395 grams.
Divide the mass of iron by its atomic weight to get the moles of iron in the oxide, and divide the mass of oxygen by its atomic weight to get the moles of oxygen in the oxide. From those two numbers, you should be able to determine the ratio of moles of oxygen to moles of iron, and then use that to determine the formula.
2007-01-23 02:36:58 · answer #1 · answered by hcbiochem 7 · 0⤊ 0⤋
There are two forms of iron oxide. The one is Fe(2)O(3) and the other one i think is FeO
2007-01-23 10:32:36 · answer #2 · answered by kyriacos d 2 · 0⤊ 1⤋
The one exact answer is Fe2O3.
This is the calculation: 0.920/55.85 = 0.0165 mol of Fe;
1.315 - 0.920 = 0395 g of O ---> 0.395/16 = 0.0247 mol of O.
Well, 0.0247/0.0165 = 3/2, which involves a formula of Fe2O3.
2007-01-23 10:55:14 · answer #3 · answered by Len M 3 · 0⤊ 0⤋