Find the value of p so the function below will not have a vertical asysmpote g(x)=(3x+p)/(x^3+8) its a integer

Answer 1

When x=-2 the denominator will equal zero. To prevent a vertical asymptote, 3(-2)+p must also be zero: therefore, p=6.

Answer 2

you can write the denominator as (x+2)*(x^2-2x+4) becaus e -2 is a root.
So it aloso should be a root f the numerator
so if x=-2 3(-2)+p=0 ===> p= 6. and you can simplify
There are NO other roots in the denominator

g(x) =3/(x^2-2x+4)