2007-01-23 01:45:51 · 5 answers · asked by niranjan_shah2003 1 in Science & Mathematics ➔ Mathematics
With one equation, you cannot get unique values for the three entities a, b and c.
.At the most you can expand and simplify the equation
2007-01-23 16:53:08 · answer #1 · answered by grandpa 4 · 0⤊ 0⤋
First simplify the equation
16abc-14(12a*12b+12c)=14 (using the rule of multiplication before addition within the brackets, which is probably the point of the question)
16abc - 14(144ab + 12c) = 14
16abc - 2016ab - 168c = 14
you now have three unknowns, a,b,c and cannot resolve any further without more information, there are no substitutions that you can make to simplify further
2007-01-23 10:40:05 · answer #2 · answered by srrl_ferroequinologist 3 · 0⤊ 0⤋
if a=2
2=3
c=4
then 16abc-14(12a*12b+12c)=14*884,571429
it seems to be a stupid solution but i cannot figure out anything else
2007-01-23 10:04:41 · answer #3 · answered by wendy 2 · 0⤊ 0⤋
Let's answer this differently.
If you are looking for solutions in integers, there are none.
The left -hand side is divisible by 4, but the right-
hand side isn't.
2007-01-23 11:48:52 · answer #4 · answered by steiner1745 7 · 0⤊ 0⤋
One equation...three unknowns...whatcha gonna do?
16abc - 2016ab -168c = 14
8abc - 1008ab - 84c = 7
I'd love to see that "simple multiplication" trick.
2007-01-23 09:58:19 · answer #5 · answered by gebobs 6 · 0⤊ 0⤋